Homework help...

unit321

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No...:snoop:

I distinctly remember never going to college algebra in HS. Bad decision.
Some high schools teach college algebra, if you are ahead of the game.
You should ask around for math tutors, they are free in college, usually. You seem to be behind.
 

tater

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The average adult would have problems with Algebra. :manny:

Well thanks for making me feel slightly better...lol

I'm going to work on this other problem and post my answers. Please don't laugh.
 

tater

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Some high schools teach college algebra, if you are ahead of the game.
You should ask around for math tutors, they are free in college, usually. You seem to be behind.

I was in the class in HS! :damn:

I tried to clep out of this class :shaq2:

I haven't done math in almost 10 years...so don't belittle me :sadbron:
 

Splash

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I think this is great I must say. You could do anything with your own time but you trying to get better at math :ld:
Keep progressing :blessed:
 

tater

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The number of home-schooled children in the US in millions is estimated by the equation y = 0.08x + 0.83, where x is the number of years after 1999. What year will the number of home schooled students exceed 2.0 million? You have to state the year! (Sec 1.5)


0.08x + 0.83 ≥ 2.0

0.08x ≥ 2.0 – 0.83

0.08x ≥ 1.17

x ≥ 14.625

Therefore, 14.625 + 1999 = 2013 so they year would be equal to or greater than the year 2013


So I did a problem like this last week that I got right, but I'm not understanding exactly what to plug into the equation. Is this like linear regression? If so, I would set the equation equal to 2.000001 correct? This exceeds the 2 mil mark, but the answer is the same as what the professor solved. For my answer I say it's between 2013-14, but that gives the same value for x once it's rounded that was previously solved.
 
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