Homework help...

Audemar

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So I did a problem like this last week that I got right, but I'm not understanding exactly what to plug into the equation. Is this like linear regression? If so, I would set the equation equal to 2.000001 correct? This exceeds the 2 mil mark, but the answer is the same as what the professor solved. For my answer I say it's between 2013-14, but that gives the same value for x once it's rounded that was previously solved.
I'm not quite sure what your question is. For inequalities, the approach you posted was correct. "x" denotes number of years after 1999 and you have a value of 14.625, 15 for a clean number. 1999+15=...
 
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