Lets see how many of yall know the right answer to this problem

[YoungMasterGold]

x/y

If x = 6 and y = 2(1+2)

6/2(1+2) = 9

The answer is still 9, even if the problem is presented algebraically.

Um, no. Doing it in the way I described means you solve for "y" before reintroducing it into the equation. Therefore, y = 2(1+2) means y = 6. Then it's brought to bear in the equation. I assumed that was clear.

In any case, giving precedence to an operation means that it is taken care of first. One must get rid of the brackets first before division occurs. That's why the whole is: y = 2(1+2).

6 / 2(3)

is the exact same thing as

6 / 2 * 3

How would you solve that?

They are not the exact same thing. I think I've sussed out where the problem lies. It's false equivalence. If brackets and multiply meant exactly the same thing, you wouldn't need parentheses as operators.

To answer your question. 6/2(3) = 1, while 6/2*3 = 9.

 

[South Paw]

They are not the exact same thing. I think I've sussed out where the problem lies. It's false equivalence. If brackets and multiply meant exactly the same thing, you wouldn't need parentheses as operators.

To answer your question. 6/2(3) = 1, while 6/2*3 = 9.

I disagree. Using the parentheses around a single number is just a shortcut to not have to use the * symbol.

Just like how 2(3) is the same as 2 * 3

 

[YoungMasterGold]

I disagree. Using the parentheses around a single number is just a shortcut to not have to use the * symbol.

Just like how 2(3) is the same as 2 * 3

Nah. While 2(3) is an instruction to multiply, it takes on an added meaning in an equation: the denotation of an operation in its own right.

 

[Ninjaz In Paris]

 

[Nigerianwonder]

6 / 2(3)

is the exact same thing as

6 / 2 * 3

How would you solve that?

lol. Those are 2 completely different expressions. The problem with the internet is dumb fukkers like you get to have an opinion. The answer is 1. The only way to not get 1 is to rewrite the expression like you just did above. The brackets are there for a reason. If they didn't want you to consider them, they would not have been written into the problem.

 

[PYRRHUS 88]

Um, no. Doing it in the way I described means you solve for "y" before reintroducing it into the equation. Therefore, y = 2(1+2) means y = 6. Then it's brought to bear in the equation. I assumed that was clear.

In any case, giving precedence to an operation means that it is taken care of first. One must get rid of the brackets first before division occurs. That's why the whole is: y = 2(1+2).




They are not the exact same thing. I think I've sussed out where the problem lies. It's false equivalence. If brackets and multiply meant exactly the same thing, you wouldn't need parentheses as operators.

To answer your question. 6/2(3) = 1, while 6/2*3 = 9.

Parentheses aren't operators, they're symbols used for grouping. 2(3) means exactly 2*3. Multiplication is implied by just placing two terms beside each other, so A*B can just be written AB. The only thing the () are doing in 2(3) is informing you that it's 2*3 and not the number 23.

 

[Data-Hawk]

Um, no. Doing it in the way I described means you solve for "y" before reintroducing it into the equation. Therefore, y = 2(1+2) means y = 6. Then it's brought to bear in the equation. I assumed that was clear.

In any case, giving precedence to an operation means that it is taken care of first. One must get rid of the brackets first before division occurs. That's why the whole is: y = 2(1+2).




They are not the exact same thing. I think I've sussed out where the problem lies. It's false equivalence. If brackets and multiply meant exactly the same thing, you wouldn't need parentheses as operators.

To answer your question. 6/2(3) = 1, while 6/2*3 = 9.

uhh. 6/2(3) is the samething as 6/2 * 3. you only do whats inside of the parenthese first.

 

[PYRRHUS 88]

lol. Those are 2 completely different expressions. The problem with the internet is dumb fukkers like you get to have an opinion. The answer is 1. The only way to not get 1 is to rewrite the expression like you just did above. The brackets are there for a reason. If they didn't want you to consider them, they would not have been written into the problem.

6/2(3) - Wolfram|Alpha

6/(2(3)) - Wolfram|Alpha

 

[Ohene]

Parentheses aren't operators, they're symbols used for grouping. 2(3) means exactly 2*3. Multiplication is implied by just placing two terms beside each other, so A*B can just be written AB. The only thing the () are doing in 2(3) is informing you that it's 2*3 and not the number 23.

 

[ThaBoyBam]

9 in 2 seconds

 

[concise]

There is a reason why things aren't written in this ridiculous format and the proper amounts of parentheses are used and division signs are discarded for forward slashes once you leave 8th grade.

 

[YoungMasterGold]

Parentheses aren't operators, they're symbols used for grouping.

Um, you do realise "parentheses" is first in the order of OPERATORS rule, right? You may have overlooked that.

2(3) means exactly 2*3.

Except, like I said earlier, when it takes on an added meaning in an equation.

Multiplication is implied by just placing two terms beside each other, so A*B can just be written AB. The only thing the () are doing in 2(3) is informing you that it's 2*3 and not the number 23.

You've got it all muddled, friend.

uhh. 6/2(3) is the samething as 6/2 * 3. you only do whats inside of the parenthese first.

And what is connected - as a whole - to the parentheses.

 

[Data-Hawk]

Um, you do realise "parentheses" is first in the order of OPERATORS rule, right? You may have overlooked



And what is connected - as a whole - to the parentheses.

you cant be serious. you do whats inside of the () first. thats it.



here put the equation into google and wolfman alpha and tell me what you get.

i'll wait.

3 by itself inside of the () means nothing

 

[PYRRHUS 88]

Um, you do realise parentheses is first in the order of OPERATORS rule, right? You may have overlooked that.

You mean the order of OPERATIONS rule? IE, perform any operations inside the parentheses first. You may have overlooked that operations =/= operators.

 

[Data-Hawk]

6/2(1+2) = 6/2(3)
6/2(1+2) = 6/2 x 3
6/2(1+2) = 6/2 • 3


stop putting the 2 inside of the ()