Solve this Math problem

[Full Measures]

A used car dealer complains to his friend that today has been a bad day. He has sold two cars, he tells his friend, for $750 each. One of the sales yielded him a 25% profit. On the other one he took a loss of 25%. "What are you worrying about?" asks his friend. "You had no loss whatsoever." "On the contrary, a substantial one," answered the dealer. Who is right?

 

[ADK]

tl:dr

 

[Heat]

It depends on how much it cost initially when he bought the cars

 

[definition]

The original values of the cars were $600 on the "profit car," (125% of which is $750) but $1000 on the "loss car" (75% of which is $750).

So he takes the L.

 

[Deadpool1986]

A used car dealer complains to his friend that today has been a bad day. He has sold two cars, he tells his friend, for $750 each. One of the sales yielded him a 25% profit. On the other one he took a loss of 25%. "What are you worrying about?" asks his friend. "You had no loss whatsoever." "On the contrary, a substantial one," answered the dealer. Who is right?

The Salesman!!!
2 cars - $750 each.
Car 1 made a 25% profit, so that ment he only paid $ 600.00 for the car ($600x25%=750)
Car2 made a 25% loss, so that ment he paid $ 937.50 for the car ($750x25%=937.50)

Now to break it down..

600 + ? = 750.. that would be $150
937.50 - ? = 750.. that would be $ 187.50

So the loss he occurred is $ 37.50

 

[Poh SIti Dawn]

I did it lol, the dealer had no loss.

 

[Falcon]

He lost because he spent time but gained no money.

 

[heisenburrr]

I was coming in here expecting all kinds of Xs & Ys

are you stupid

 

[Full Measures]

It depends on how much it cost initially when he bought the cars

problem didn't say breh

 

[Full Measures]

I was coming in here expecting all kinds of Xs & Ys

are you stupid

Solve the problem with your work showing if you so smart then fukk nikka

 

[Heat]

problem didn't say breh

I despise math

 

[heisenburrr]

Solve the problem with your work showing if you so smart then fukk nikka

The original values of the cars were $600 on the "profit car," (125% of which is $750) but $1000 on the "loss car" (75% of which is $750).

So he takes the L.

 

[Egomaniacal1]

I'mma say the profit car cost him $562.50 while the loss car cost him $1000...total he put on it $1562.50.

He sold the two for $1500 which means he took a loss of $62.50...not really substantial but a loss nonetheless.

Edit: gonna agree the profit car was $600. So redoing the numbers he spent $1600 to get $1500 so $100 loss.

 

[Full Measures]

I looked at the solution. @Deadpool1986 got that shyt right. And he showed his work too

What were you grades in math like breh?

Edit: I thought he smashed it. Nobody got it right yet.

 

[definition]

I looked at the solution. @Deadpool1986 got that shyt right. And he showed his work too

What were you grades in math like breh?

He was close. But he multiplied the $750 times 1.25 to get the $937.50 ... which is not how you figure out the original cost of the loss car. you divide 750 by 0.75 (to reflect the loss of 25%). Original cost was 1000.

Showing your work only helps if you're doing the right work.