Solve this Math problem

Joined
May 2, 2012
Messages
604
Reputation
120
Daps
784
Reppin
NULL
Why are people still answering wrong on this? The answer was provided way early in the thread

Cost of Profit Car = x
Cost of Loss Car = y

x + .25x = 750 y -.25y = 750
1.25x = 750 .75y = 750
x= 600 y = 1000
$150 Profit $250 Loss

250-150 = $100 Loss
 

Orbital-Fetus

cross that bridge
Supporter
Joined
May 5, 2012
Messages
42,004
Reputation
19,143
Daps
155,442
Reppin
Humanity
(x) 1.25 = 750

(x) .75 = 750

been a while since i got my math on but i think i'm on to something.
 

Full Measures

All Star
Joined
Nov 23, 2013
Messages
2,911
Reputation
-150
Daps
6,015
Why are people still answering wrong on this? The answer was provided way early in the thread

Cost of Profit Car = x
Cost of Loss Car = y

x + .25x = 750 y -.25y = 750
1.25x = 750 .75y = 750
x= 600 y = 1000
$150 Profit $250 Loss

250-150 = $100 Loss

The way you broke this down cuz :ohhh:
 

definition

im not a cool guy anymore
Joined
Jun 11, 2012
Messages
761
Reputation
360
Daps
1,103
Aight well how come we can't get the answer by just taking 25% from 750 and so forth?

because 25% of 750 is not information you need.

you need to know what value would result in 750 after you take away 25%.

Same with the profit car, only that's easier. You are looking for the number that, after a 25% gain, would result in 750.

Hence the need for the algebra ...
 

Data-Hawk

I have no strings on me.
Joined
May 6, 2012
Messages
8,423
Reputation
1,995
Daps
16,333
Reppin
Oasis
Thought this was about to be another one of those facebook problems.
 

Orbital-Fetus

cross that bridge
Supporter
Joined
May 5, 2012
Messages
42,004
Reputation
19,143
Daps
155,442
Reppin
Humanity
A used car dealer complains to his friend that today has been a bad day. He has sold two cars, he tells his friend, for $750 each. One of the sales yielded him a 25% profit. On the other one he took a loss of 25%. "What are you worrying about?" asks his friend. "You had no loss whatsoever." "On the contrary, a substantial one," answered the dealer. Who is right?

:lupe:

(x) 1.25 = 750

(y) .75 = 750

been a while since i got my math on but i think i'm on to something.


car one cost him = 600
car two = 1000

car one plus car two cost him = 1600

he made 1500 for both cars.

the "substantial one" loss he took was the 1600 he paid minus the 1500 he made


yeah...it took me a minute to figure it out.



he paid 1600 for both cars but only made 1500 after the sales.
25% of x does not equal 25% of y....


i've made multiple corrections in this post but i think i have it nailed down now.




*final edit*

got it.
 
Last edited:
Top