You run a shop and someone steals $100

Zach Lowe

what up beck
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No
You're dumb. Write the problem as a math variable.

Guys loses 100 dollars = -100
Guy gains 60 dollars back from the stolen money but loses 60 from giving away merchandise so it evens out back to the original -100.
Guy gives 40 back in change so now it's at -140



Total loss= 140
following your logic

what if the customer didn't steal 100 to begin with

storekeeper gets $60 cash for the product
loses $60 by giving the product in exchange
and gives back $40 in change

so +60-60-40
and he lost $40?
:childplease:
 

Claudex

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In order to get change he'd have to have handed you the stolen $100 bill back. At which point you'd be even.

You give him $60 in merch and $40 in cash you are only back to the original $100. There is no extra $40

You'd be even except for the fact that he didn't use HIS money to make a purchase, he used YOUR money. When he came through with your $100 it's not like you were on $0, nah nikka you were already operating your business on -$100.

If he stole your money and then came to make a deal with you you're gonna have a transaction based on a loss.

Usually if I make a purchase with my money it goes like this:

Seller = $0
Me = $100

But in this case this is how the transaction ocurred:

Seller = -$100
Buyer = $100
 

Zach Lowe

what up beck
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No I didn't, he lost the $60 too, he basically gave it away free
buying the product and getting change back is a valid transaction you retard

if the storekeeper "loses" from that then he loses on every sale and he's a retard

the only theft is the $100 stolen
by buying the $60 worth of shyt the thief trades part of his stolen cash for product

the loss to the storekeeper is only $100 cuz the thief got $60 of product and $40 cash

the loss to storekeeper = amount stolen by the thief

:snoop: coli retarded
 

DrunkenNovice

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following your logic

what if the customer didn't steal 100 to begin with

storekeeper gets $60 cash for the product
loses $60 by giving the product in exchange
and gives back $40 in change

so +60-60-40
and he lost $40?
:childplease:

Edit my bad breh...you understood :scheme:

Coli brehs let me know when yall open a shop
 

MeachTheMonster

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You'd be even except for the fact that he didn't use HIS money to make a purchase, he used YOUR money. When he came through with your $100 it's not like you were on $0, nah nikka you were already operating your business on -$100.

If he stole your money and then came to make a deal with you you're gonna have a transaction based on a loss.

Usually if I make a purchase with my money it goes like this:

Seller = $0
Me = $100

But in this case this is how the transaction ocurred:

Seller = -$100
Buyer = $100
-100 + 100 = 0 :francis:

And If he used his own money we wouldn't be even.

fukk kinda logic is that. :dahell:
 

Zach Lowe

what up beck
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No
You're dumb. Write the problem as a math variable.

Guys loses 100 dollars = -100
Guy gains 60 dollars back from the stolen money but loses 60 from giving away merchandise so it evens out back to the original -100.
Guy gives 40 back in change so now it's at -140



Total loss= 140
"Guy gains 60 dollars back from the stolen money but loses 60 from giving away merchandise so it evens out back to the original -100."

you're assuming the storekeeper makes no money on sales?

"Guy gives 40 back in change so now it's at -140"
so what if the $100 was the customer's own money (not stolen)
by your logic, if he buys something worth $60 that's a zero sum transaction (+60-60 = 0)
then if you give him $40 in change back, you lost $40 :dahell:


nah
 
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