Deadpool1986
Cook with a Mouth
I looked at the solution. @Deadpool1986 got that shyt right. And he showed his work too
What were you grades in math like breh?![]()
They were OK, nothing special!!
I looked at the solution. @Deadpool1986 got that shyt right. And he showed his work too
What were you grades in math like breh?![]()
He was close. But he multiplied the $750 times 1.25 to get the $937.50 ... which is not how you figure out the original cost of the loss car. you divide 750 by 0.75 (to reflect the loss of 25%). Original cost was 1000.
Showing your work only helps if you're doing the right work.
The Salesman!!!
2 cars - $750 each.
Car 1 made a 25% profit, so that ment he only paid $ 600.00 for the car ($600x25%=750)
Car2 made a 25% loss, so that ment he paid $ 937.50 for the car ($750x25%=937.50)
Now to break it down..
600 + ? = 750.. that would be $150
937.50 - ? = 750.. that would be $ 187.50
So the loss he occurred is $ 37.50
I looked at it again you halfway right. Deadpool was right about the salesman being right. But his work was wrong about the second car and how much he lost
im with you on the first car. but shouldnt the second car og orice be 1000$ a 25% loss would make that to 750.
so he made 150 on car 1. lost 250 on car 2. dude lost 100 in the end

smh yall nikkas dumb
u supposed to multiply 25% x 750 on the first car. then u get 187.50 .
theres a 250 dollar loss on the second car so the obvious answer is he lost 62.50 . @Full Measures

I'mma say the profit car cost him $562.50 while the loss car cost him $1000...total he put on it $1562.50.
He sold the two for $1500 which means he took a loss of $62.50...not really substantial but a loss nonetheless.
Edit: gonna agree the profit car was $600. So redoing the numbers he spent $1600 to get $1500 so $100 loss.
nah ur teacher is wrong sonThat's wrong cuz.![]()
im with you on the first car. but shouldnt the second car og orice be 1000$ a 25% loss would make that to 750.
so he made 150 on car 1. lost 250 on car 2. dude lost 100 in the end